![]() Using the above Short circuit MVA values of each component in the SLD, draw the MVA diagram as shown below. Short Circuit of MVA of Transmission Line MVA4 = KV 2/Impedance in ohms Voltage rating of Transmission line= 33KV Short Circuit of MVA of Transformer MVA3 = MVA/Impedance in per unit Short Circuit of MVA of Generator-B MVA2 = MVA/Sub-transient reactance of generator in per unit Short Circuit of MVA of Generator-A MVA1 = MVA/Sub-transient reactance of generator in per unit Draw the Required System The system described in the problem is shown in Figure 2. Step-1:Ĭonvert all single line components in the given SLD to short circuit MVA’s. Identify the Appropriate Symbols For electric power networks an appropriate selection of graphic symbols is shown in Figure 1 (common power symbols used in single line diagrams): Figure 1 Common power symbols used in single line diagrams 2. The solution is given below, solved using the above mentioned procedure in three steps. Let’s see how to calculate the fault current using MVA Method at Points F1 and F2. Solving the given Network using MVA Method:
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